How to calculate years between B.C. and now?

Question

Hi. I'm trying to find out how to calculate how many years it has been between 4 BCE and now from the time of Jesus's birth.

How far was 4BCE from 2613 B.C.?

and how far was 2613 B.C. from now?

I'm having the hardest time calculating the dates. Can someone please give me the formula for solving this as well?

Answer 1

BCE (Before Common Era) dates are the same as B.C. (Before Christ) dates. It's just another name for the same thing.



4 BCE to 5 BC is 1 year. 5 - 4 = 1

4BCE to 2613 BC is 2609 years. 2613 - 4 = 2609.



There is no year "0". The counting goes 4 BC, 3 BC, 2 BC, 1 BC, 1 AD, 2 AD, etc.

2613 to 1 BC is 2612 years.

1 BC to 1 AD is 1 year.

1 AD to 2011 is 2010 years.

Total is 4623 years.

Answer 2

The BCE years act as 'negatives' and you can just subtract. For instance, -2613--4 (note the extra - sign, we are subtracting a negative number from a negative number) gives -2609, so January 1, 4 BCE would be 2609 years after January 1, 2613 BCE.



The sticky point is when converting past BCE and CE dates. There is no 'year zero', and January 1, 1 CE was exactly one year after January 1, 1 BCE. This, despite the fact that 1--1 gives 2. You have to subtract 1 from the result to correct for the missing 'year zero'.



Further complicating matters is the fact that different calendars are used in different places and at different times. Sometimes a correction has to be made for this as well.

Answer 3

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Answer 4

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Don't believe anyone who tells you it's a simple math problem. This is not a straightforward math problem because THERE IS NO YEAR ZERO. So it's math plus a big dollop of common sense. But there is another issue before I can answer. You are asking 2 different questions. Between is the word confusing the issue. I'll tell you how to figure them based on a simple example and then you can sub any actual dates you want. The crucial years to consider are these, the 4 consecutive years around the change of era: 2 BC 1 BC 1 AD 2 AD Question 1: How many years are between 2 BC and 2 AD ? We have to be careful of that word 'between'. Example: "How many states are between New York and Ohio?" The answer is one (Pennsylvania) because you do not count the states you are talking about.. So 'years between' can describe a group of years not including the extreme years There are two years in between 2 BC and 2 AD, namely 1 BC and 1 AD. Question 2 "How many years passed from 2 BC and 2 AD?" Three. We add one year for each year that passes. 2 BC to 1 BC is one year, 1 BC to 1 AD is one year, and 1 AD to 2 AD is one year = three years. In this question we DO include the end year because don't get to it unless we do.

Answer 5

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RE:

How to calculate years between B.C. and now?

Hi. I'm trying to find out how to calculate how many years it has been between 4 BCE and now from the time of Jesus's birth.



How far was 4BCE from 2613 B.C.?



and how far was 2613 B.C. from now?



I'm having the hardest time calculating the dates. Can someone please give me the...

Answer 6

4 BCE = -4

2613 BC = -2613



BC and BCE are different names for the same thing. -4 - (-2613) = 2613 - 4 = 2609.



As far as calculating from BCE to CE, you just have to account for the fact that there was no 0 AD. The year after 1 BC/BCE was 1 AD/CE.



So 2011 - (-2613) = 4624, but subtract 1 for the missing year 0. 2613 BCE was 4623 years ago.

Answer 7

BCE = BC (Before Common Era = Before Christ),

CE = AD (Common Era = Anno Domini).

From 31.Oct.1BCE to 31.Oct.1CE = 1 yr,

So just add the 2 yrs (BCE+CE) & subtract 1 because there's no yr 0.

This calendar era is based on the traditionally reckoned year of the conception or birth of Jesus of Nazareth, with AD counting years from the start of this epoch, and BC denoting years before the start of the era. There is no year zero in this scheme, so the year AD 1 immediately follows the year 1 BC. This dating system was devised in 525CE, but was not widely used until after 800CE. By then, obviously, no one knew with any accuracy when exactly Jesus was born so it's an approximation.

Answer 8

2609



2011 plus 2613 = 4624

Answer 9

add the BC with BCE and subtract 1 for year 0

4+2613-1=2616 years



same concept for next one

formula=BC+BCE-1

2613+2011-1=4623 years

Answer 10

What would be the age of someone who was born in 1320BC today

Answer 11

Add them together and subtract 1.



There was no year "zero."

Answer 12

Add the BS to the BCSE...then you got your answer....straight from the mad cow's posterior

Answer 13

360B C